the diagonals of a rhombus measure 16 cm and 30 cm. find its perimeter
Answers
Answered by
0
Answer:
240
Step-by-step explanation:
perimeter of rhombus
=1/2×D1×D2
=1/2×16×30
=240
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Answered by
2
Answer:
Perimeter = 68cm
Step-by-step explanation:
Diagonal AC = 16cm
Diagonal BD = 30cm
Since diagonals of a rhombus bisect each other perpendicularly,
OA = OC = 8cm
OB = OD = 15cm
In right triangle OAB, using Pythagoras theorem,
AB² = OA² + OB²
= 8² + 15²
= 64 + 225
= 289
= 17²
AB = 17 cm
∴ Perimeter = 4 × AB
= 4 × 17
= 68 cm
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