Question

the diagonals of a rhombus measure 16 cm and 30 cm  .find its perimeter    ( in easy way)

Answer 1

Thanks for asking the question.
Diagnol of a rhombus bisect each other at right angle.
So,
     One side of a rhombus= square root of (8^2+15^2)
                                         = square root of(64+225)
                                        = square root of(289)
                                         =17cm
Perimeter of rhombus=4(side)
                                   =4*17
                                  = 68cm
Hope it helps.