the diagonals of a rhombus measure 16 cm and 30 cm .find its perimeter ( in easy way)
Answers
Answered by
9
Thanks for asking the question.
Diagnol of a rhombus bisect each other at right angle.
So,
One side of a rhombus= square root of (8^2+15^2)
= square root of(64+225)
= square root of(289)
=17cm
Perimeter of rhombus=4(side)
=4*17
= 68cm
Hope it helps.
Diagnol of a rhombus bisect each other at right angle.
So,
One side of a rhombus= square root of (8^2+15^2)
= square root of(64+225)
= square root of(289)
=17cm
Perimeter of rhombus=4(side)
=4*17
= 68cm
Hope it helps.
Similar questions