The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.
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Answer:
perimeter of rhombus = 68 cm
Step-by-step explanation:
let AC and BD are diagonals of rhombus
length of AC = 16 cm
length of BD = 30cm
length of AO = 8 cm
length of BO = 15cm
as per property of rhombus,
diagonals bisect at 90°
AO^2 + BO^2 = AB^2
8^2 + 15^2 = AB^2
64 + 225 = AB^2
AB^2 = 289
AB = 17 cm
as per property of rhombus,
length of sides are equal
perimeter of rhombus = 4 × side of rhombus
perimeter of rhombus = 4 × 17 cm
perimeter of rhombus = 68 cm
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