the diagonals of a rhombus measure 16 cm and 30 cm find its perimeter by pythogoras theorem
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The diagonals of the rhombus intersect at right angle.
Using half of each diagonals, we can find the hypotenuse, which is the length of the rhombus.
Find the length:
a² + b² = c²
c² = (16 ÷ 2)² + (30 ÷ 2)²
c² = 8² + 15²
c² = 289
c² = √289
c = 17
Find the Perimeter:
Perimeter = 4 x Length
Perimeter = 4 x 17 = 68 cm
Answer: The perimeter is 68 cm
khanrayhan8307:
I think your answer is right but i didn't understand it.
Can you please make it clear ?
In Pythagoras theorem, h2 = p2 + b2
Sorry that I missed your question.
The 2 diagonals intersect a a right angle, so the 1/2 diagonals of each side and the length of the side form a right angle triangle. (A quarter of the rhombus) So we Pythagoras theorem to find the length, since we know the length of the diagonals.
The 2 diagonals intersect a a right angle, so the 1/2 diagonals of each side and the length of the side form a right angle triangle. (A quarter of the rhombus) So we Pythagoras theorem to find the length, since we know the length of the diagonals.
That's OK
Answered by
6
Heya!!
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Perimeter of rhombus = 4 * under root[(d1/2)^2+ (d2/2)^2]
=) P = 4 * under root[(8^2+ 15^2]
= 4 * under root 289
= 4*17 cm = 68 cm.
Hope it helps uh!
------------------------------
Perimeter of rhombus = 4 * under root[(d1/2)^2+ (d2/2)^2]
=) P = 4 * under root[(8^2+ 15^2]
= 4 * under root 289
= 4*17 cm = 68 cm.
Hope it helps uh!
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