Question

The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.

Answer 1

Answer:

Step-by-step explanation

Let us assume that ABCD is rhombus with diagonal 16 cm and 30cm.

And let O be the point where both diagonal intersect .

Si

In ∆AOB

By Pythagoras theorem

(AB)^2=(AO)^2+(BO)^2

We know that AO =8cm and BO=15cm

SO

(AB)^2=(8×8)+(15×15)

(AB)^2=64+225

(AB)^2=289

taking square root on bith side

AB=17cm

So we know that all sides of Rhombhus are equal

Hence its perimeter is 4s

Mean 4×17

That is 68cm.

Hence perimeter of Rhombhus is 68cm.

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Answer 2

Answer:

Step-by-step explanation:

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