Question

The diagonals of a rhombus measure 16 CM and 30 CM. Find its perimeter

Answer 1

Answer:

perimeter = 68cm

Explanation:

Let x and y are two diagonals of a Rhombus.

x = 16cm , y = 30cm

side of the Rhombus =√(x/2)²+(y/2)²

= √(16/2)²+(30/2)²

= √8²+15²

= √64+225

=√289

=√17²

= 17

Side = 17 cm

Perimeter = 4×side

= 4×17

= 68cm

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