The diagonals of a rhombus measure 16 CM and 30 CM. Find its perimeter
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Answer:
perimeter = 68cm
Explanation:
Let x and y are two diagonals of a Rhombus.
x = 16cm , y = 30cm
side of the Rhombus =√(x/2)²+(y/2)²
= √(16/2)²+(30/2)²
= √8²+15²
= √64+225
=√289
=√17²
= 17
Side = 17 cm
Perimeter = 4×side
= 4×17
= 68cm
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