Question

the diagonals of a rhombus measure 16cm and 30 cm find the perimeter of rhombus. ​

Answer 1

Answer:

$perimeter \: of \: rhombus \: = 2 \sqrt{ {x}^{2} + {y}^{2} } \\ where \: x = 16 \: cm \: and \: y = 30 \: cm \\ perimeter \: of \: rhombus \: = 2 \sqrt{ {16}^{2} + {30}^{2} } \\ = 2 \sqrt{256 + 900} \\ = 2 \sqrt{1156} \\ \sqrt{1156} = 34 \\ = 2 \times 34 \\ = 68 \: cm$

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