Math, asked by banerjeeshri2373, 9 months ago

The diagonals of a rhombus measure 16cm and 30cm . Find its perimeter.

Answers

Answered by Anonymous
9

Answer:

As the diagonals of rhombus bisects each other by 90°

8²+15²=side²

64+225=side²

289=side²

√289=side

17cm =side

As the sides of rhombus are equal then

Perimeter =4*side

Perimeter =4*17

Perimeter =68cm

Answered by shrshivakumar
1

In a rhombus all sides are equal and diagonals are perpendicular bisectors

Ac2=(12)2+(15)2

=144+225

=369

=√369

=19.2

So the perimeter is 19.2cm

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