Question

The diagonals of A rhombus measure 16cm and 30cm . Find its perimeter​

Answer 1

Step-by-step explanation:

1. diagonals of Rhombus bisect each other at right angles
2. all sides of a rhombus are equal

therefore, perimeter=AB +BC+ CD+ DA

=4*AB

=136cm

hope it helps you

Answer 2

Note : The picture attached up is not mine.

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$\sf\underline{Given-}$

$\mapsto$ Diagonals of a rhombus are 16cm and 30cm.

$\sf\underline{Have \: to \: Find-}$

$\mapsto$ Perimeter of the rhombus.

$\sf\underline{Solution-}$

$\sf{As \: we \: know \: that,}$

A rhombus has four sides.

Accordingly,

$\sf{Perimeter \: of \: the \: rhombus = 4 × side}$

The diagonals of the rhombus are 16cm and 30cm,as given in the question.

Therefore ,

$\sf\blue{Side \: of \: rhombus = √(D1)^2 + (d2)^2/2}$

❍ $\sf{Side \: of \: rhombus}$

$\Rightarrow$ √(16)^2 + $\dfrac{(30)^2}{2}$

$\Rightarrow$ √256 + $\dfrac{900}{2}$

$\Rightarrow$ $\dfrac{√1156}{2}$

$\Rightarrow$ 2 × $\dfrac{17}{2}$

$\sf{=17cm}$

Hence , the side of the given rhombus is 17cm.

$\sf{Now,}$The perimeter of the rhombus :-

= 17 × 4

= 68

Therefore , the perimeter of the rhombus is $\sf\underline\blue{68cm.}$

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