Question

the diagonals of a rhombus measure 16cm and 30cm find its perimeter​

Answer 1

Refer to the attachment!!

Answer 2

Answer:

$\huge\tt\underline{quєstíσn}$:

the diagonals of a rhombus measures 16cm and 30 cm,find its perimeter

$\huge\tt\underline{gívєn}$:

measures of diagonals of rhombus= 16cm and 30 cm

$\huge\tt\underline{tσ\:fínd}$

perimeter of the rhombus

$\huge\tt\underline{solution}$

The formula for perimeter of a rhombus where only the diagonals are known is:

$p = 2 \sqrt{ {a}^{2} + {b}^{2} }$

where,P = perimeter,and a and b are the diagonals.

with the given data:

$p = 2 \sqrt{ {16}^{2} + {30}^{2} }$

$p = 2 \sqrt{256 + 900}$

$p = 2\sqrt{1156}$

factorise to find the square root:

$p = 2\sqrt{2.2.17.17}$

$p = 2 \sqrt{34.34}$

$p = 2 \times 34$

$p = 68$

so, perimeter of the rhombus is 68cm

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