Question

The diagonals of a rhombus measure 16cm and 30cm, find its perimeter.

Answer 1

Explanation:

see the attachment

hope it helps you

Answer 2

Answer:

AC perpendicular BD

And

OB=BD/2

OB=16/2cm

OB=8cm

Now,

OA=AC/2

OA=30/2cm

OA=15cm

Now,

Using Pythagoras Theorem,

AB²=OA²+OB²

AB²=(15)²+(8)²cm

AB²=225+64cm

AB²=289cm

AB²=(17)²cm

AB=17cm

Now,

Perimeter ABCD=AB+BC+CD+CA

=AB+AB+AB+AB

= 4*AB

=4*17cm

=68cm

Hence, required perimeter=68cm