The diagonals of a rhombus measure 96 cm and 180 cm . Find its perimetes
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P=408cm
Solution
P = Diagonal = 96 cm
Q = Diagonal = 180 cm
Using the formulas
P=4a
a = p^2 + Q^2 / 2
Solving for P
P = 2 P^2 + Q^2 = 2
96^2 + 180^2 = 408 cm
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