Question

The diagonals of a rhombus measures 10 and 8 cm. Find is perimeter

Answer 1

Step-by-step explanation:

As we know that diagonals of a rombus bisect each other at 90°.

So the bisected parts are 10/2=5 cm and 8/2=4 cm

Now in Right Angle Triangle,p=4 cm,b=5cm.

So h=✓b^+p^2=✓5^2+4^2=✓25+16=✓41

So perimeter of rombus=4×✓41=4✓41 cm