Question

the diagonals of a rhombus measures 10 cm and 24 cm find its perimeter

Answer 1

According to question,

AC= 24 cm and BD=10 cm

we need to find the perimeter

AE=EC=12 cm and BE=ED=5 cm (Property 2)

Now, in triangle AED, By Pythagoras Theorem

AD^2= AE^2 + ED^2

AD^2= 12^2 + 5^2

AD^2= 144 + 25

AD^2= 169

AD = 13 cm

Perimeter = AB+BC+CD+DA = 13+13+13+13= 52cm 

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