the diagonals of a rhombus measures 10 cm and 24 cm find its perimeter
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According to question,
AC= 24 cm and BD=10 cm
we need to find the perimeter
AE=EC=12 cm and BE=ED=5 cm (Property 2)
Now, in triangle AED, By Pythagoras Theorem
AD^2= AE^2 + ED^2
AD^2= 12^2 + 5^2
AD^2= 144 + 25
AD^2= 169
AD = 13 cm
Perimeter = AB+BC+CD+DA = 13+13+13+13= 52cm
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AC= 24 cm and BD=10 cm
we need to find the perimeter
AE=EC=12 cm and BE=ED=5 cm (Property 2)
Now, in triangle AED, By Pythagoras Theorem
AD^2= AE^2 + ED^2
AD^2= 12^2 + 5^2
AD^2= 144 + 25
AD^2= 169
AD = 13 cm
Perimeter = AB+BC+CD+DA = 13+13+13+13= 52cm
If you like answer please Mark as BRAINLIST and follow me.
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