The diagonals of a rhombus measures 14cm and 24cm. Find its perimeter
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Diagonals meet at the centre and forms right-angled triangles.
So by using pythagoras theorem
Length of the base = 14/2 = 7cm
Length of the height = 24/2 = 12cm
Hypotenuse2 = side 2+ side2
hypotenuse 2= 7^2 +12^2
Hypotenuse2 = 49 + 144
Hypotenuse2 = 196
On taking square root we get,
Hypotenuse = 14 { 14X 14=196 => √196=14}
Hence the side of the rhombus is 14cm.
Perimeter of the rhombus = 4×side
= 4 × 14
= 56cm.
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