Math, asked by khadeejazafar9431, 1 year ago

The diagonals of a rhombus measures 16 cm and 30 cm.Find its perimeter

Answers

Answered by sebasstheking
4
Diagonals of perimeter are perpendicular to each other . So ,we can use Pythagorean theorem to find the side length of rhombus . Diagonal = 16/2 = 8cm Diagonal = 30/2 = 15cm 82+152 = s2 64+225 = 289 = s2 Side length(s) = 17 Perimeter of rhombus = 4*17 = 68 cm
Answered by shriyaptn2008
2

HEY MATE HERE IS YOUR ANSWER

Answer:

68 cm

Step-by-step explanation:

given,the measures of diagonals16,30

We know that diagonals of rhombus are perpendicular bisectors of each other.

db=16

DO=DB/2

DO=16/2

DO=8cm

similarly,AO=15cm

by using pythogaras theorem,

DO²+AO²=DA²

8²+15²=DA²

64+225=DA²

289=DA²

DA=17

perimeter=DA×4

=17×4

PERIMETER=68CM

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