Question

the diagonals of a rhombus measures 18 cm and 24 cm find its perimeter

Plese tell in an understandable way. Others were quite confusing.​

Answer 1

Hey mate your answer
Hope it helps!!

Answer 2

Step-by-step explanation:

⇝ Given :

Diagonals of the Rhombus = 18 cm and 24 cm

⇝ Formula of perimeter of Rhombus :

P=4a

Only when diangonals are given use this below formula ,

$P = 2 \sqrt{p^{2}+ q^{2}$

⇝ Explanation :

$2\sqrt{8^{2} + 24^{2}} = {P}$

$2 * \sqrt{900}$

2 * 30

60

Hope you understood,

Have a great day ahead...