The diagonals of a rhombus meauser 24 cm and 10cm, respectively. Find the length of the sides of the rhombus.
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Answer:
Step-by-step explanation:
The diagonals of rhombus are perpendicular bisectors
In □ABCD
diagonals intersect at point o
AO=OC
BO=OD
AB=24
BD=10
AO=1÷2OF 24
BO=1÷2OF 10
AO=12
BO=5
IN triangle AOB
(AO)^2+(OB)^2=(AB)^2
144+25=(AB)^2
169=(AB)^2
Square root of 169 =(AB)
13=(AB)
All sides of rhombus are congruent
AB=BC=CD=AD=13
sandipvasava:
Thanks sir
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