The diagonals of a rohumbus measure 8cm and 6cm.Find it's perimeter
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Answer:
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Step-by-step explanation:
let D1 be 6cm=6/2=3cm
D2 be 8cm=8/2=4cm
Using Pythagoras theorem:
AC²+AB²=BC²
3²+4²=BC²
9+16=BC²
25=BC²
√25=BC
5cm=BC
hence (S)side=5cm
perimeter=4*S
4*5=20cm
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