The diagonals of a square are perpendicular bisects of each other.Prove the statement.
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Proof: Consider ΔAOD and ΔAOB
AD = AB (Sides of a square are equal).
OD = OB (Diagonals of a square bisect each other).
AO = AO (Common side)
∴Using SSS congruency rule, ΔAOD ≈ to ΔAOB
⇒∠AOD = ∠AOB.
As ∠AOD + ∠AOB = 1800
∴∠AOD = 900.
∴ AO ⊥ BD
Hence, AC ⊥ BD.
AD = AB (Sides of a square are equal).
OD = OB (Diagonals of a square bisect each other).
AO = AO (Common side)
∴Using SSS congruency rule, ΔAOD ≈ to ΔAOB
⇒∠AOD = ∠AOB.
As ∠AOD + ∠AOB = 1800
∴∠AOD = 900.
∴ AO ⊥ BD
Hence, AC ⊥ BD.
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here is ur answer .in this attachment..
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