Question

The diagonals of a square is 72 cm .find the side of the square ​

Answer 1

answer is 36.........

Answer 2

Solution :

Let

• ABCD is Square.
• Its Diagonal be 72 Cm.

Now, We know

• All sides of square be equal.
• Angle 90°

So,

Apply Pythagoras theorem.

$\tt \dagger \: \: \: \: \: {H}^{2} = {P}^{2} + {B}^{2}$

Here,

• H = diagonal of Square ( 72 cm )
• P ( sides of square 'a' )
• B ( sides of square 'a' )

$\tt \longmapsto {72}^{2} = {a}^{2} + {a}^{2}$

$\tt \longmapsto 5184 = 2 {a}^{2}$

$\tt \longmapsto \dfrac{5184}{2} = {a}^{2}$

$\tt \longmapsto 2592 = {a}^{2}$

$\tt \longmapsto a = 50.91 \: cm.$

Therefore, the value of sides of square be 50.91 Cm.

$\rule{200}3$

Note :Figure provide in attachment