The diagonals of a square with area 9 m2
divide the square into four non-overlaping
triangles. What is the sum of the perimeter
of the four triangles?
(A) 12 m
(B) 12root 2
(C) 12+12root2
(D) None of these
Answers
Answered by
5
Answer:
28.97
Step-by-step explanation:
he diagonals of a square with area 9 square divide square into four known non overlapping Triangles what is the sum of the perimeter of the four triangles
Area of a square = Side²
=> Side² = 9
=> Side = 3
Diagonal Length = 3√2
Perimeter of 4 non overlapping Triangles
= Sum of 4 sides + twice * Both diagonals
=4 * 3 + 2*2 *3√2
= 12 + 12√2
= 12 + 16.97
= 28.97
MAKE THIS BRAINLIEST
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