Math, asked by sharmakashish1602, 11 months ago

The diagonals of an isosceles trapezoid are represented by 4x -47 and 2x + 31. what is the value of x?

Answers

Answered by ummeremarat
42

Step-by-step explanation:

4x-47 =2x+31

=4x-2x=31+47

=2x=78

x=78/2

=39

x=39

Answered by qwsuccess
22

Given,

The trapezoid is isosceles.

The diagonals of trapezoid are represented as 4x-47 and 2x+31.

To Find,

The value of x.

Solution,

We all know that an isosceles trapezoid's diagonals are congruent.

That's why we can say that here,

4x-47=2x+31.

⇒4x-2x=31+47.

⇒2x=78.

⇒x=\frac{78}{2}=39.

Hence, the value of x is 39.

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