Math, asked by Rahmanaqdas4042, 1 year ago

The diagonals of parallelogram abcd intersect in point o. if ∠boc = 90° and ∠bcd = 50° then ∠oab = ?

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Answered by vandanasthana14
0
DAB=BCD=50° and ABO=1/2of DAB=25°(diagonals bisects angle) and AOB =180-BOC=90° and ABO +AOB+BAO=180° which gives ABO=65°.
Answered by tanrit
4

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