The diagonals of parallelogram abcd intersect in point o. if ∠boc = 90° and ∠bcd = 50° then ∠oab = ?
Answers
Answered by
0
DAB=BCD=50° and ABO=1/2of DAB=25°(diagonals bisects angle) and AOB =180-BOC=90° and ABO +AOB+BAO=180° which gives ABO=65°.
Answered by
4
Answer:
Step-by-step explanation:
Mark as brainlist . If helpful
Attachments:
Similar questions