The diagonals of rectangle 43 . find its primeter and area
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Answer:
Solution:
Given:
=> Length of rectangle = 40 cm
=> Diagonal of rectangle = 41 cm.
To Find:
=> Perimeter of rectangle.
Formula used:
=> Pythagoras Theorem.
=> Perimeter of rectangle.
So, Let ABCD be a rectangle and AC is the diagonal of rectangle. We know that all angle of rectangle is 90°.
So, by using Pythagoras theorem we will find breadth.
=> AB² + BC² = AC²
=> AB² + 40² = 41²
=> AB² + 1600 = 1681
=> AB² = 1681 - 1600
=> AB² = 81
=> AB = 9 cm.
So, breadth of rectangle is 9 cm.
Perimeter of rectangle = 2(L + B)
=> 2(40 + 9)
=> 2(49)
=> 98 cm
So, perimeter of rectangle is 98 cm.
Step-by-step explanation:
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