Math, asked by ProudOnIndian, 5 months ago

The diagonals of rectangle 43 . find its primeter and area​

Answers

Answered by Anonymous
0

Answer:

Solution:

Given:

=> Length of rectangle = 40 cm

=> Diagonal of rectangle = 41 cm.

To Find:

=> Perimeter of rectangle.

Formula used:

=> Pythagoras Theorem.

=> Perimeter of rectangle.

So, Let ABCD be a rectangle and AC is the diagonal of rectangle. We know that all angle of rectangle is 90°.

So, by using Pythagoras theorem we will find breadth.

=> AB² + BC² = AC²

=> AB² + 40² = 41²

=> AB² + 1600 = 1681

=> AB² = 1681 - 1600

=> AB² = 81

=> AB = 9 cm.

So, breadth of rectangle is 9 cm.

Perimeter of rectangle = 2(L + B)

=> 2(40 + 9)

=> 2(49)

=> 98 cm

So, perimeter of rectangle is 98 cm.

Step-by-step explanation:

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