Question

The diagonals of rectangle abcd intersect at o. If boc= 40 find boa

Answer 1

Answer:

∠boa = 140° (angle)

boa = 40 (length)

Step-by-step explanation:

The diagonals of rectangle abcd intersect at o. If boc= 40 find boa

abcd is rectangle

and diagonals intersect at o

so ∠boc  & ∠boa will be supplementary angles

as ac diagonal is a straight line

∠boc + ∠boa = 180°

=> 40° + ∠boa = 180°

=> ∠boa = 140°

If we say boc = 40 is length

then boc = bo + oc = 40

then boa = bo + oa

oa = oc as digonal is bisected at intersection point

boa = bo + oc = 40