Math, asked by Anonymous, 10 months ago

the diagonals of rectangle abcd intersect at o . if boc= 70 degree then find oda and abo

Answers

Answered by gaintboy70509000

Step-by-step explanation:

Given in rectangle ABCD, ∠BOC = 70°

∠BOC = ∠AOD [Vertically opposite angles are equal]

∠AOD = 70°

Since diagonal of a rectangle are equal and they bisect each other.

We can write OA = OB = OC = OD

Hence DAOD is an isosceles triangle.

⇒∠OAD = ∠ODA [Angles opposite to equal sides of a triangle are equal]

Let ∠OAD = ∠ODA = x

∠OAD + ∠ODA +∠AOD = 180°

⇒ x + x + 70° = 180°

⇒ 2x = 110°

⇒ x = 55°

Hence ∠ODA = 55°

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Answered by useridaasim

Given in rectangle ABCD, ∠BOC = 70°

∠BOC = ∠AOD [Vertically opposite angles are equal]

∠AOD = 70°

Since diagonal of a rectangle are equal and they bisect each other.

We can write OA = OB = OC = OD

Hence DAOD is an isosceles triangle.

⇒∠OAD = ∠ODA [Angles opposite to equal sides of a triangle are equal]

Let ∠OAD = ∠ODA = x

∠OAD + ∠ODA +∠AOD = 180°

⇒ x + x + 70° = 180°

⇒ 2x = 110°

⇒ x = 55°

Hence ∠ODA = 55°

Anonymous: thnku!!

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