Math, asked by prachippandey2005, 11 months ago

The diagonals of rectangle ABCD intersects at O. If angle AOB = 64°, find angle OCB.

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Answered by Anonymous

Hope this helps..

Answer is 116 degree. ..

angle C = angle B =90° [ corner angles of a rectangle is 90°]

1/2 angle C = 1/2 angel B

Angle OCB= angle OBC ---------(1)

In ∆ OBC

angle OBC +angle OCB +angle BOC=180°

Angle OCB+angle OCB + 116° = 180° [from eq 1]

2angle OCB = 180°-116°

2angle OCB = 64°

Angle OCB = 64°/2

angle OCB = 32°

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prachippandey2005: Answer is 32°...

prachippandey2005: It's incorrect. I am also not getting it.

Anonymous: Yah sorry ... i thought the answer is asking the value of angle COB

Anonymous: Hey I edited the answer this one is correct

prachippandey2005: Yes u r right.... Thank u so much

Answered by Anonymous

Answer:

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ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘs ᴜʜ...⭐

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