The diagonals of rhambus measures 16 cm and 30 cm
Find its perimeter.
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Given: Diagonals AC=30cm and DB=16cm.
Since the diagonals of the rhombus bisect at right angle to each other.
Therefore, OD= DB/2 = 16/2 = 8cm
and OC = AC/2 = 30/2 = 15 cm
Now, In right angle triangle DOC,
( DC )2 = ( OD )2 + ( CO )2
=> ( DC )2 = ( 8 )2 + ( 15 )2
=> ( DC ) 2 = 64 + 225 = 289
=> DC = √289 = 17 cm
Perimeter of the rhombus = 4 * side
= 4 * 17 cm
= 68 cm.
Thus the perimeter of the rhombus is 68 cm.
HOPE YOU FOUND MY ANSWER CORRECT.
HAVE A GOOD DAY !!
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