Math, asked by suneelchauhan227, 10 months ago

The diagonals of Rhombus ABCD intersect at O. if AC =12cm and BD =16cm, find the length of its side​

Answers

Answered by aslamm1
0

Answer:

We know that, diagonals in a rhombus bisect each other perpendicularly.

Let O is the intersecting point of diagonals AC and BD.

OA=  

2

AC

​  

=  

2

16

​  

=8cm

OB=  

2

BD

​  

=  

2

12

​  

=6cm

Now, in △AOB,∠AOB=90  

o

 

⇒  (AB)  

2

=(OA)  

2

+(OB)  

2

                [ By Pythagoras theorem ]

⇒  (AB)  

2

=(8)  

2

+(6)  

2

 

⇒  (AB)  

2

=64+36

⇒  (AB)  

2

=100

∴  AB=10cm

We know that, all sides of rhombus are equal.

∴   The length of each side of rhombus is 10cm

Step-by-step explanation:

Similar questions