Question

the diagonals of rhombus are 20and 21 respectively then find the sides of rhombus

Answer 1

We know that in a rhombus the diagonals bisect each other at 90


so let AC=20 AND BD=21 CM
AD=10 AND BO=10.5 CM
AB^2=AD^2+OB^2
=10^2+10.5^2
=100+110.25
=210.25
AB=14.5 IS THE SIDE OF THE RHOMBUS
Hope it helps