Question

the diagonals of rhombus are 8.5 cm and 14cm.Find it's area​

Answer 1

$given -$

$the \: two \: diagnoals \: of \: a \: rhombus \: \\ are \: 8.5 \: cm \: and \: 14 \: cm$

$to \: find -$

$area \: of \: rhombus$

$solution -$

$area \: of \: rhombus -\:$

$= \frac{1}{2} \times d1 × d2$

$= \frac{1}{2} \times 8.5 \times 14$

$= \frac{1}{2} \times 119$

$= 59.5$

Answer 2

Know That:

• Every rhombus has two diagonals connecting pairs of opposite vertices, and two pairs of parallel sides.

According To The Question:

Given That:

• Diagonals of the rhombus = 8.5cm and 14cm.

To Calculate:

• The area of the rhombus.

Calculation:

Let d¹ and d² be the two diagonals of the rhombus.

Where,

• d¹ = 1st diagonal of the rhombus
• d² = 2nd diagonal of the rhombus

Then,

• d¹ = 8.5 cm
• and d² = 14 cm

We Already Know That,

• Area of a Rhombus = 1/2 × (Product Of Diagonals) sq. units

Now Solving After Substituting The Values:

Area of the rhombus ➝ (1/2 × 8.5 × 14)cm²

 ⠀  ⠀  ⠀  ⠀  ⠀  ⠀  ⠀   ➝ 59.5cm²

Required Answer:-

↬ Hence, the area of the rhombus is 59.5cm².

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