Question

the diagonals of rhombus is 15 and 36 long find its perimeter

Answer 1

Hey mate !!!!

here is your answer!!!

let the side be X

DAIGONAL of Rhombus is => 15 cm and 36 CM

hence the DAIGONAL divided in to equal parts so

DAIGONAL will be => 7.5 cm

and 18cm

now using Pythagoras theroum .

we get

=> x ² = (7.5)² + 18²

=> X ² =√380

X = 19. 5 ( approx )

now , perimeter of rohmbus => 4 x side

4 x 19.5

=> 78 cm

hope it helps you dear!!!

thanks

Answer 2

Hi there !!
Here's your answer

Let's first mark the vertices as A, B , C , D and the intersection of their diagonal as O [ check my attachment]

Here's the method now :

To find the perimeter, we need to find the side of the rhombus :

AC = 15cm , AO = OC = 15/2 = 7.5 cm [ diagonals bisect each other ]
BD = 36cm , DO = OB = 36/2 = 18cm

We'll find the side using the PYTHAGORAS THEOREM :
so,
we have,

DO² + OC² = DC²
18² + 7.5² = DC²
DC² = 324 + 56.25
DC² = 380.25
DC = ✓380.25
DC = 19.5

Thus,
the side is 19.5 cm

Perimeter of Rhombus = 4 × side
Perimeter = 4 × 19.5cm
Perimeter = 78cm

Thus,
the perimeter is 78cm

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Hope it helps !!