Question

The diagonals of rhombus measure 16 cm and 30 cm. find its perimeter.

Answer 1

Answer:

area = 1/2×d1×d2

1/2×16×30=

240cm Ans

Answer 2

since the diagonals of rhombus bisect each other perpendicularly .

then let ABCD be a rhombus and diagonals meet at O.

OA=1/2AC=8

OB=1/3BD=15

now angle AOB = 90°

so by Pythagoras theorem

in triangle AOB

AB=17

and sides are equal in rhombus

therefore perimeter= 4*side = 4*17 = 68