Question

The diagonals of the rectangle ABCD intersect At O. If angle COD is 78 then angle OAB

Answer 1

Answer:

in triangle OAB, angle aob = 78

angle oab and angle oba are equal

therefore aob +oab+ oba =180

78 + oab + oba =180

oab + oba = 180 - 78 = 102

2× oab = 102

oab =51 Ans