The diagonals of the rectangle ABCD intersect at O. If ∠COD = 82֯, then ∠OAB is:
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Answer:
∠OAB = 49°
Step-by-step explanation:
∠COD=∠AOB=82° ...(Vertically opposite)
And we know that diagonals of a rectangle bisect each other.
∴ΔAOB is an isosceles triangle with AB as the base.
We also know that base angles of isosceles triangle are equal and the angles of triangle sums up to 180°
∴We can take ∠OAB=∠OBA=x
Now in ΔAOB,
∠OAB+∠OBA+∠AOB=180°
x+x+82=180
2x+82=180
2x=98
x=98/2
x=49
Hope this helps!
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