Math, asked by kindadumb, 1 month ago

The diagonals of the rectangle ABCD intersect at O. If ∠COD = 82֯, then ∠OAB is:​

Answers

Answered by an1307
1

Answer:

∠OAB = 49°

Step-by-step explanation:

∠COD=∠AOB=82°                                  ...(Vertically opposite)

And we know that diagonals of a rectangle bisect each other.

∴ΔAOB is an isosceles triangle with AB as the base.

We also know that base angles of isosceles triangle are equal and the angles of triangle sums up to 180°

∴We can take ∠OAB=∠OBA=x

Now in ΔAOB,

∠OAB+∠OBA+∠AOB=180°

x+x+82=180

2x+82=180

2x=98

x=98/2

x=49

Hope this helps!

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