Question

The diagonals of the rhombus 12cm and 16cm. Find its perimeter

Answer 1

Answer:

Step-by-step explanation:

Diagonal of rhombus = 12cm and 16cm

half of diagonal = 6cm and 8cm

a (side) of rhombus = √p² + b²

a = √6² + 8² = √36+64 =√ 100 = 10cm

now , as we know that Perimeter of rhombus

= 4a = 4×10 = 40cm

#answerwithquality #BAL

Answer 2

d1 = 12 cm

d2 = 16 cm

a = $\sqrt{(\frac{12}{2})^{2}+{(\frac{16}{2})^{2} }} =\sqrt{8^{2}+6^{2}  }= \sqrt{100}=10$cm (Diagonals of a rhombus bisect each other at 90°)

= 4a = 4×10 = 40cm

#BAL #answerwithquality