Question

the diagonals of the rhombus are 10 centimetre and 24 cm find the perimeter of rhombus ​

Answer 1

BY USING PATHAGOREAN FORMULA.

${h}^{2} = {b}^{2} + {h}^{2}$

${h }^{2} = {5}^{2} + {12}^{2}$

${h}^{2} = 25 + 144 \\ {h}^{2} = 169 \\ h = \sqrt{169 } = 13cm$

THE SIDE OF RHOMBUS IS 13 CM.

PERIMETER OF RHOMBUS =4*SIDE

=4*13=52 cm Ans

Answer 2

Diagonals of a rhombus bisects at 90 degrees.

=>sides of the right angled triangle are

=12cm and 5cm (excluding hypotenuse)

By Pythagoras,

12^2+5^2=H^2 (where H=side of rhombus)

After Calculation,

H=13cm

As all sides of a rhombus are equal,

:. Perimeter=4*13=52cm