Question

The diagonals of the rhombus are 16 cm and 12 cm . Find its sides​

Answer 1

Answer:

a=10

Step-by-step explanation:

a=√d1^2+d2^2/2

a=√(16^2+12^2)/2

a=√(256+144)/2

a=√400/2

a=20/2

a=10

Answer 2

Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒ We know that the diagonals of rhombus bisect at right angles.

⇒

AO= 16/2

=8cm

BO= 12/2

=6cm

In right angled △AOB,

By using Pythagoras theorem,

⇒ AB²=AO²+BO²

⇒AB²= 8²+6²

⇒AB²= 64+36

⇒AB²=100

⇒AB=√100

⇒AB=10

∴ Side of a rhombus is 10cm.