Question

the diagonals of the Rhombus is 24m and 10 metres. find the perimeter​

Answer 1

According to question,

AC= 24 cm and BD=10 cm

we need to find the perimeter

AE=EC=12 cm and BE=ED=5 cm (Property 2)

Now, in triangle AED, By Pythagoras Theorem

AD^2= AE^2 + ED^2

AD^2= 12^2 + 5^2

AD^2= 144 + 25

AD^2= 169

AD = 13 cm

Perimeter = AB+BC+CD+DA = 13+13+13+13= 52cm (Property 1)

Answer 2

Answer:

If the diagonals measure 24 cm and 10 cm, then by the Pythagorean theorem each side has a length of 13 cm.

Therefore, the perimeter of the rhombus is equal to 4 x 13 or 52 cm. 68 cms.

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