the diagonals of the rhombus PQRS intersect at O. if PR=10 CM AND QS=24CM FIND LENgthof it's sides
indu1237493:
Sorry for the mistake in calculation
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Answered by
25
Hii mate !!!
Here is your answer....
Diagonals of a rhombus bisect each other at 90° angle
So length of PO = PR/2 = 10/2= 5cm
And length of OS = QS/2=24/2=12cm
In triangle POS using pythagoras theorem
(PS)^(2) = (PO)^(2) + (OS)^(2)
(PS)^(2) = (5)^(2) + (12)^(2)
(PS)^(2) = 25 + 144
(PS) = √ (25+144)
PS = √169
PS = 13cm
Therefore length of the side of rhombus is 13cm...
HOPE THIS WILL HELP YOU...
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17
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