Question

The diagonals of two squares are in the ratio 3 : 2 Frete ratio of their areas​

Answer 1

$length \: of \: Diagonal \: of \: Square = \sqrt{2} a$

$a = side \: of \: \: square$

$Let \: side \: of \: both \: Square \: be \\ \: a1  \: and \: a2$

$\sqrt{2} \: a1 \: : \sqrt{2} \: a2 = 3 : 2$

$a1 \: and \: a2 = 3 \: : 2$

$( {a1)}^{2} \: \ \: : ( {a2)}^{2} = {3}^{2} \: \ \: : {2}^{2}$

$( {a1)}^{2} \: \ \: : ( {a2)}^{2} = 9 \: \ \: : 4$

Answer 2

Answer:

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Step-by-step explanation:

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