The diagonals ofa rhombus are given how to find sides
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hey there,
Following from the comments, the best we can do is give a relation between the sum of the square of the lengths of the diagonals. If ABCDABCD is a rhombus with side length xx then, by the parallelogram law, and because we know each side has equal length, we know that 4x2=|AC|2+|BD|24x2=|AC|2+|BD|2 where |AC||AC| is the length of the diagonal from AA to CC and similarly for |BD||BD| .
In the case of a square, we get |AC|=|BD||AC|=|BD| and so 2x2=|AC|2⇒|AC|=2–√⋅x
Hope this helps!
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