The diagonals PR and SQ of a rhombus PQRS intersect at O.
If PR= 10 cm and SQ= 24 cm then find the length of PQ.
Answers
Answer:
HEYY....
Step-by-step explanation:
Diagonals of a rhombus bisect each other at 90° angle
So length of PO = PR/2 = 10/2= 5cm
And length of OS = QS/2=24/2=12cm
In triangle POS using pythagoras theorem
(PS)^(2) = (PO)^(2) + (OS)^(2)
(PS)^(2) = (5)^(2) + (12)^(2)
(PS)^(2) = 25 + 144
(PS) = √ (25+144)
PS = √169
PS = 13cm
Therefore length of the side of rhombus is 13cm...
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Answer:
Given :-
The diagonals PR and SQ of a rhombus PQRS intersect at O.
PR= 10 cm and SQ= 24 cm.
To find :- Length PQ.
Solution :-
Diagonals of rhombus bisect each other at 90°.
1/2 PR = 10/2 = 5.
1/2 SQ = 24/2 = 12.
Using pythagoras theorem.
PQ ^2 = PO^2 + QO^2.
= 5 ^2 + 12^2
= 25 + 144
PQ = √169
PQ = 13
Answer : Length of PQ is 13.
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