The diagonalsOF Q RHOMBUS are 9CM and 14CM), Find the area.
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Answer:
The diagonals of Rhombus are 9cm and 14cm
Area of Rhombus = product of two diagonals/2
Area of Rhombus = 9 × 14 /2
Area of Rhombus = 126/2
Area of Rhombus = 63
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Let , rhombus is PQRS and diagonals are PR and QS .
Given, one diagonals is 9cm and another is 14 cm . Then, PR = 9cm, QS= 14cm .
Area of rhombus= d1.d1 x d2.d2 /2 sq.
=3x3 x14/2x14/2 ( diagonals bisect each other)
=9x14
=126 sq.
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