The diagounal of a rhombus are 15cm and 36 cm. Find its perimeter.
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Perimeter of rhombus d1 +d2=15+36=51
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Hey!!
Let the side be x
Diagonal of rhombus are 15 cm and 36 cm ( given )
Hence the diagonal divided in two equal parts
Diagonal will be 7.5 cm and 18 cm
Now,
By using Pythagoras theorem
=> x^2 = ( 7. 5 ) ^2 + 18^2
=> x^2 = 56.25 + 324
=> x = √380
=> x = 19.5 ( approx )
Perimeter of rhombus = 4 × side
=> 4 × 19.5
=> 78 cm
Hope it will helps you!
Let the side be x
Diagonal of rhombus are 15 cm and 36 cm ( given )
Hence the diagonal divided in two equal parts
Diagonal will be 7.5 cm and 18 cm
Now,
By using Pythagoras theorem
=> x^2 = ( 7. 5 ) ^2 + 18^2
=> x^2 = 56.25 + 324
=> x = √380
=> x = 19.5 ( approx )
Perimeter of rhombus = 4 × side
=> 4 × 19.5
=> 78 cm
Hope it will helps you!
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