The diagram below (Fig. 1.32) shows a uniform bar
supported at the middle point 0. A weight of 40 gf is
placed at a distance 40 cm to the left of point O.
How can you balance the bar with a weight of
80 gf?
40 gf
O
50 40
30 20
10
10 20
30 40
50 cm
Fig. 1.32
Answers
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Answer:
Anticlockwise moment = 40gf × 40 cm
Clockwise moment = 80 gf × d cm
From the principle of moments,
Anticlockwise moment = Clockwise moment
40 gf × 40 cm = 80 gf × d
So, d = 40gf x 40/80 = 20cm to the righte of point O.
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