The diagram below shows the map of a pentagonal park. Find the length of side ‘x’
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Solution :-
Construction :- Join EB . and denotes all points .
using pythagoras theorem we get,
→ EB = √[CD² + (BC + DE)²]
→ EB = √[4² + (3 + 5)²]
→ EB = √(16 + 64)
→ EB = √80
then, in right angled ∆ABE again using pythagoras theorem we get,
→ AE = √[EB² - AB²]
→ x = √[(√80)² - 3²]
→ x = √(80 - 9)
→ x = √71 (Ans.)
[ Note :- since diagram is not to the scale , we can't take AB = where D cuts at AE . ]
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Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी.
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