Question

the diagram below shows the position of two divers A and B in river water at the depth of h1 and h2 respectively from the water surface .
(1).Which of the two divers(AorB)will experience more pressure by the water?
(2).The two divers were later made to dive in a sea. For the same depth, they experience more pressure in the sea compared to that in the river. Why? ​

Answer 1

Answer:

Part a)

Diver B will experience more pressure

Part b)

Due to large value of density in sea water diver will experience more pressure

Explanation:

Part a)

As we know that the pressure due to fluid inside the liquid surface is given as

$P = \rho g H$

here we know that

$\rho$ = density of liquid

h = depth from the surface of the liquid

Now we know that the diver B is at more depth as compare to diver A

So diver B will experience more pressure

Part b)

As we know that density of sea water is more than the water because it is having salts in it

So due to large value of density it will the diver will experience more pressure inside sea water as compare to the water

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Topic : Pressure inside the liquid

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Answer 2

Answer:

bottom supports the weight of the fluid in it. Let us calculate the pressure exerted on the bottom by the weight of the fluid. That pressure is the weight of the fluid mg divided by the area A supporting it (the area of the bottom of the container):

P

=

m

g

A

.

We can find the mass of the fluid from its volume and density:

m = ρV.

The volume of the fluid V is related to the dimensions of the container. It is

V = Ah,

where A is the cross-sectional area and h is the depth. Combining the last two equations gives

m

=

ρ

A

h

.

If we enter this into the expression for pressure, we obtain

P

=

(

ρ

A

h

)

g

A

.

The area cancels, and rearranging the variables yields

P = hρg.