The diagram given below shows a ski jump. A skier weighing 60kgf stands at A at the top of ski jump. He moves from A and takes off for his jump. (g = 10m/s2) (i) The change in the gravitational potential energy of the skier between A and C is:
1. 42000J
2. 4200J
3. 4.2J
4.130J
(ii) The kinetic energy at point C is:
1. 42000J
2. 4200J
3. 4.2J
4.130J
(iii) The total energy at the point E is:
1. 60000J
2. 42000J
3. 4.2J
4.130J
(iv) The law which holds good for this case is:
1. Newton’s first law
2. Law of conservation of momentum
3. Law of conservation of energy
4. Newton’s law of gravitation
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Answer:
(a) Mass of skier =60kg
Loss in potential energy =mg(h
1
−h
2
)
60×10×(75−15)
=60×10×60=3.6×10
4
J
(b) Kinetic energy at B=
100
75
×3.6×70
4
=27000J
=2.7×10
4
J
Kinetic energy =
2
1
mv
2
27000=
2
1
mv
2
27000=
2
1
×60×v
2
v
2
=
30
27000
=900
V=30/,m/s
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